3(2k+3)=7k-1

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Solution for 3(2k+3)=7k-1 equation: 



3(2k+3)=7k-1

We move all terms to the left:

3(2k+3)-(7k-1)=0

We multiply parentheses

6k-(7k-1)+9=0

We get rid of parentheses

6k-7k+1+9=0

We add all the numbers together, and all the variables

-1k+10=0

We move all terms containing k to the left, all other terms to the right

-k=-10

k=-10/-1

k=+10

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