3(2k+3)=9k-15

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Solution for 3(2k+3)=9k-15 equation:



3(2k+3)=9k-15
We move all terms to the left:
3(2k+3)-(9k-15)=0
We multiply parentheses
6k-(9k-15)+9=0
We get rid of parentheses
6k-9k+15+9=0
We add all the numbers together, and all the variables
-3k+24=0
We move all terms containing k to the left, all other terms to the right
-3k=-24
k=-24/-3
k=+8

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