3(2k+4)=-2(k-5)

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Solution for 3(2k+4)=-2(k-5) equation: 



3(2k+4)=-2(k-5)

We move all terms to the left:

3(2k+4)-(-2(k-5))=0

We multiply parentheses

6k-(-2(k-5))+12=0



We calculate terms in parentheses: -(-2(k-5)), so:

-2(k-5)

We multiply parentheses

-2k+10

Back to the equation:

-(-2k+10)



We get rid of parentheses

6k+2k-10+12=0

We add all the numbers together, and all the variables

8k+2=0

We move all terms containing k to the left, all other terms to the right

8k=-2

k=-2/8

k=-1/4

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