3(2k+4)=2(3k+6)

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Solution for 3(2k+4)=2(3k+6) equation: 



3(2k+4)=2(3k+6)

We move all terms to the left:

3(2k+4)-(2(3k+6))=0

We multiply parentheses

6k-(2(3k+6))+12=0



We calculate terms in parentheses: -(2(3k+6)), so:

2(3k+6)

We multiply parentheses

6k+12

Back to the equation:

-(6k+12)



We get rid of parentheses

6k-6k-12+12=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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