3(2k-15)-k=4-(3k+7)

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Solution for 3(2k-15)-k=4-(3k+7) equation:



3(2k-15)-k=4-(3k+7)
We move all terms to the left:
3(2k-15)-k-(4-(3k+7))=0
We add all the numbers together, and all the variables
-1k+3(2k-15)-(4-(3k+7))=0
We multiply parentheses
-1k+6k-(4-(3k+7))-45=0
We calculate terms in parentheses: -(4-(3k+7)), so:
4-(3k+7)
determiningTheFunctionDomain -(3k+7)+4
We get rid of parentheses
-3k-7+4
We add all the numbers together, and all the variables
-3k-3
Back to the equation:
-(-3k-3)
We add all the numbers together, and all the variables
5k-(-3k-3)-45=0
We get rid of parentheses
5k+3k+3-45=0
We add all the numbers together, and all the variables
8k-42=0
We move all terms containing k to the left, all other terms to the right
8k=42
k=42/8
k=5+1/4

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