3(2k-15)-k=4-(3k+7)

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Solution for 3(2k-15)-k=4-(3k+7) equation: 



3(2k-15)-k=4-(3k+7)

We move all terms to the left:

3(2k-15)-k-(4-(3k+7))=0

We add all the numbers together, and all the variables

-1k+3(2k-15)-(4-(3k+7))=0

We multiply parentheses

-1k+6k-(4-(3k+7))-45=0



We calculate terms in parentheses: -(4-(3k+7)), so:

4-(3k+7)

determiningTheFunctionDomain
-(3k+7)+4

We get rid of parentheses

-3k-7+4

We add all the numbers together, and all the variables

-3k-3

Back to the equation:

-(-3k-3)



We add all the numbers together, and all the variables

5k-(-3k-3)-45=0

We get rid of parentheses

5k+3k+3-45=0

We add all the numbers together, and all the variables

8k-42=0

We move all terms containing k to the left, all other terms to the right

8k=42

k=42/8

k=5+1/4

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