3(2k-2)-4(k+1)=

Solution for 3(2k-2)-4(k+1)= equation:

Simplifying
3(2k + -2) + -4(k + 1) = 0

Reorder the terms:
3(-2 + 2k) + -4(k + 1) = 0
(-2 * 3 + 2k * 3) + -4(k + 1) = 0
(-6 + 6k) + -4(k + 1) = 0

Reorder the terms:
-6 + 6k + -4(1 + k) = 0
-6 + 6k + (1 * -4 + k * -4) = 0
-6 + 6k + (-4 + -4k) = 0

Reorder the terms:
-6 + -4 + 6k + -4k = 0

Combine like terms: -6 + -4 = -10
-10 + 6k + -4k = 0

Combine like terms: 6k + -4k = 2k
-10 + 2k = 0

Solving
-10 + 2k = 0

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + 2k = 0 + 10

Combine like terms: -10 + 10 = 0
0 + 2k = 0 + 10
2k = 0 + 10

Combine like terms: 0 + 10 = 10
2k = 10

Divide each side by '2'.
k = 5

Simplifying
k = 5