3(2k-2)=8k+22

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Solution for 3(2k-2)=8k+22 equation: 



3(2k-2)=8k+22

We move all terms to the left:

3(2k-2)-(8k+22)=0

We multiply parentheses

6k-(8k+22)-6=0

We get rid of parentheses

6k-8k-22-6=0

We add all the numbers together, and all the variables

-2k-28=0

We move all terms containing k to the left, all other terms to the right

-2k=28

k=28/-2

k=-14

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