3(2k-5)+24=k-(3k+7)

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Solution for 3(2k-5)+24=k-(3k+7) equation: 



3(2k-5)+24=k-(3k+7)

We move all terms to the left:

3(2k-5)+24-(k-(3k+7))=0

We multiply parentheses

6k-(k-(3k+7))-15+24=0



We calculate terms in parentheses: -(k-(3k+7)), so:

k-(3k+7)

We get rid of parentheses

k-3k-7

We add all the numbers together, and all the variables

-2k-7

Back to the equation:

-(-2k-7)



We add all the numbers together, and all the variables

6k-(-2k-7)+9=0

We get rid of parentheses

6k+2k+7+9=0

We add all the numbers together, and all the variables

8k+16=0

We move all terms containing k to the left, all other terms to the right

8k=-16

k=-16/8

k=-2

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