3(2k-5)-k=-4-(3k+7)

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Solution for 3(2k-5)-k=-4-(3k+7) equation: 



3(2k-5)-k=-4-(3k+7)

We move all terms to the left:

3(2k-5)-k-(-4-(3k+7))=0

We add all the numbers together, and all the variables

-1k+3(2k-5)-(-4-(3k+7))=0

We multiply parentheses

-1k+6k-(-4-(3k+7))-15=0



We calculate terms in parentheses: -(-4-(3k+7)), so:

-4-(3k+7)

determiningTheFunctionDomain
-(3k+7)-4

We get rid of parentheses

-3k-7-4

We add all the numbers together, and all the variables

-3k-11

Back to the equation:

-(-3k-11)



We add all the numbers together, and all the variables

5k-(-3k-11)-15=0

We get rid of parentheses

5k+3k+11-15=0

We add all the numbers together, and all the variables

8k-4=0

We move all terms containing k to the left, all other terms to the right

8k=4

k=4/8

k=1/2

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