3(2k-5)=4-7k/2

Solution for 3(2k-5)=4-7k/2 equation:

3(2k-5)=4-7k/2

We move all terms to the left:

3(2k-5)-(4-7k/2)=0

We add all the numbers together, and all the variables

3(2k-5)-(-7k/2+4)=0

We multiply parentheses

6k-(-7k/2+4)-15=0

We get rid of parentheses

6k+7k/2-4-15=0

We multiply all the terms by the denominator


6k*2+7k-4*2-15*2=0

We add all the numbers together, and all the variables

7k+6k*2-38=0

Wy multiply elements

7k+12k-38=0

We add all the numbers together, and all the variables

19k-38=0

We move all terms containing k to the left, all other terms to the right

19k=38

k=38/19

k=2