3(2k-7)=26

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Solution for 3(2k-7)=26 equation:



3(2k-7)=26
We move all terms to the left:
3(2k-7)-(26)=0
We multiply parentheses
6k-21-26=0
We add all the numbers together, and all the variables
6k-47=0
We move all terms containing k to the left, all other terms to the right
6k=47
k=47/6
k=7+5/6

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