3(2m)=5(m+1)

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Solution for 3(2m)=5(m+1) equation: 



3(2m)=5(m+1)

We move all terms to the left:

3(2m)-(5(m+1))=0



We calculate terms in parentheses: -(5(m+1)), so:

5(m+1)

We multiply parentheses

5m+5

Back to the equation:

-(5m+5)



We get rid of parentheses

32m-5m-5=0

We add all the numbers together, and all the variables

27m-5=0

We move all terms containing m to the left, all other terms to the right

27m=5

m=5/27

m=5/27

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