3(2m+3)-4m=8m+27

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Solution for 3(2m+3)-4m=8m+27 equation: 



3(2m+3)-4m=8m+27

We move all terms to the left:

3(2m+3)-4m-(8m+27)=0

We add all the numbers together, and all the variables

-4m+3(2m+3)-(8m+27)=0

We multiply parentheses

-4m+6m-(8m+27)+9=0

We get rid of parentheses

-4m+6m-8m-27+9=0

We add all the numbers together, and all the variables

-6m-18=0

We move all terms containing m to the left, all other terms to the right

-6m=18

m=18/-6

m=-3

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