3(2m+4)=3(98-2m)

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Solution for 3(2m+4)=3(98-2m) equation: 



3(2m+4)=3(98-2m)

We move all terms to the left:

3(2m+4)-(3(98-2m))=0

We add all the numbers together, and all the variables

3(2m+4)-(3(-2m+98))=0

We multiply parentheses

6m-(3(-2m+98))+12=0



We calculate terms in parentheses: -(3(-2m+98)), so:

3(-2m+98)

We multiply parentheses

-6m+294

Back to the equation:

-(-6m+294)



We get rid of parentheses

6m+6m-294+12=0

We add all the numbers together, and all the variables

12m-282=0

We move all terms containing m to the left, all other terms to the right

12m=282

m=282/12

m=23+1/2

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