3(2m+4)=6+15

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Solution for 3(2m+4)=6+15 equation: 



3(2m+4)=6+15

We move all terms to the left:

3(2m+4)-(6+15)=0

We add all the numbers together, and all the variables

3(2m+4)-21=0

We multiply parentheses

6m+12-21=0

We add all the numbers together, and all the variables

6m-9=0

We move all terms containing m to the left, all other terms to the right

6m=9

m=9/6

m=1+1/2

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