3(2m+5)=9m-27

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Solution for 3(2m+5)=9m-27 equation: 



3(2m+5)=9m-27

We move all terms to the left:

3(2m+5)-(9m-27)=0

We multiply parentheses

6m-(9m-27)+15=0

We get rid of parentheses

6m-9m+27+15=0

We add all the numbers together, and all the variables

-3m+42=0

We move all terms containing m to the left, all other terms to the right

-3m=-42

m=-42/-3

m=+14

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