3(2m-1)+4=6(m+1)

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Solution for 3(2m-1)+4=6(m+1) equation: 



3(2m-1)+4=6(m+1)

We move all terms to the left:

3(2m-1)+4-(6(m+1))=0

We multiply parentheses

6m-(6(m+1))-3+4=0



We calculate terms in parentheses: -(6(m+1)), so:

6(m+1)

We multiply parentheses

6m+6

Back to the equation:

-(6m+6)



We add all the numbers together, and all the variables

6m-(6m+6)+1=0

We get rid of parentheses

6m-6m-6+1=0

We add all the numbers together, and all the variables

-5!=0

There is no solution for this equation

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