3(2m-1)=2(m+4)+1

Solution for 3(2m-1)=2(m+4)+1 equation:

3(2m-1)=2(m+4)+1

We move all terms to the left:

3(2m-1)-(2(m+4)+1)=0

We multiply parentheses

6m-(2(m+4)+1)-3=0


We calculate terms in parentheses: -(2(m+4)+1), so:

2(m+4)+1

We multiply parentheses

2m+8+1

We add all the numbers together, and all the variables

2m+9

Back to the equation:

-(2m+9)


We get rid of parentheses

6m-2m-9-3=0

We add all the numbers together, and all the variables

4m-12=0

We move all terms containing m to the left, all other terms to the right

4m=12

m=12/4

m=3