3(2m-8)=-19+7m

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Solution for 3(2m-8)=-19+7m equation: 



3(2m-8)=-19+7m

We move all terms to the left:

3(2m-8)-(-19+7m)=0

We add all the numbers together, and all the variables

3(2m-8)-(7m-19)=0

We multiply parentheses

6m-(7m-19)-24=0

We get rid of parentheses

6m-7m+19-24=0

We add all the numbers together, and all the variables

-1m-5=0

We move all terms containing m to the left, all other terms to the right

-m=5

m=5/-1

m=-5

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