3(2n+1)-(n-6)=29

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Solution for 3(2n+1)-(n-6)=29 equation: 



3(2n+1)-(n-6)=29

We move all terms to the left:

3(2n+1)-(n-6)-(29)=0

We multiply parentheses

6n-(n-6)+3-29=0

We get rid of parentheses

6n-n+6+3-29=0

We add all the numbers together, and all the variables

5n-20=0

We move all terms containing n to the left, all other terms to the right

5n=20

n=20/5

n=4

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