3(2n+2)+n=-1+6(n+2)

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Solution for 3(2n+2)+n=-1+6(n+2) equation:



3(2n+2)+n=-1+6(n+2)
We move all terms to the left:
3(2n+2)+n-(-1+6(n+2))=0
We add all the numbers together, and all the variables
n+3(2n+2)-(-1+6(n+2))=0
We multiply parentheses
n+6n-(-1+6(n+2))+6=0
We calculate terms in parentheses: -(-1+6(n+2)), so:
-1+6(n+2)
determiningTheFunctionDomain 6(n+2)-1
We multiply parentheses
6n+12-1
We add all the numbers together, and all the variables
6n+11
Back to the equation:
-(6n+11)
We add all the numbers together, and all the variables
7n-(6n+11)+6=0
We get rid of parentheses
7n-6n-11+6=0
We add all the numbers together, and all the variables
n-5=0
We move all terms containing n to the left, all other terms to the right
n=5

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