3(2n+2)=5(n+2)-3

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Solution for 3(2n+2)=5(n+2)-3 equation:



3(2n+2)=5(n+2)-3
We move all terms to the left:
3(2n+2)-(5(n+2)-3)=0
We multiply parentheses
6n-(5(n+2)-3)+6=0
We calculate terms in parentheses: -(5(n+2)-3), so:
5(n+2)-3
We multiply parentheses
5n+10-3
We add all the numbers together, and all the variables
5n+7
Back to the equation:
-(5n+7)
We get rid of parentheses
6n-5n-7+6=0
We add all the numbers together, and all the variables
n-1=0
We move all terms containing n to the left, all other terms to the right
n=1

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