3(2n+2)=6(3n+2)+6

Solution for 3(2n+2)=6(3n+2)+6 equation:

3(2n+2)=6(3n+2)+6

We move all terms to the left:

3(2n+2)-(6(3n+2)+6)=0

We multiply parentheses

6n-(6(3n+2)+6)+6=0


We calculate terms in parentheses: -(6(3n+2)+6), so:

6(3n+2)+6

We multiply parentheses

18n+12+6

We add all the numbers together, and all the variables

18n+18

Back to the equation:

-(18n+18)


We get rid of parentheses

6n-18n-18+6=0

We add all the numbers together, and all the variables

-12n-12=0

We move all terms containing n to the left, all other terms to the right

-12n=12

n=12/-12

n=-1