3(2n+2)=7(7n+4)+8

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Solution for 3(2n+2)=7(7n+4)+8 equation: 



3(2n+2)=7(7n+4)+8

We move all terms to the left:

3(2n+2)-(7(7n+4)+8)=0

We multiply parentheses

6n-(7(7n+4)+8)+6=0



We calculate terms in parentheses: -(7(7n+4)+8), so:

7(7n+4)+8

We multiply parentheses

49n+28+8

We add all the numbers together, and all the variables

49n+36

Back to the equation:

-(49n+36)



We get rid of parentheses

6n-49n-36+6=0

We add all the numbers together, and all the variables

-43n-30=0

We move all terms containing n to the left, all other terms to the right

-43n=30

n=30/-43

n=-30/43

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