3(2n+2)=9(3n+2)+5

Solution for 3(2n+2)=9(3n+2)+5 equation:

3(2n+2)=9(3n+2)+5

We move all terms to the left:

3(2n+2)-(9(3n+2)+5)=0

We multiply parentheses

6n-(9(3n+2)+5)+6=0


We calculate terms in parentheses: -(9(3n+2)+5), so:

9(3n+2)+5

We multiply parentheses

27n+18+5

We add all the numbers together, and all the variables

27n+23

Back to the equation:

-(27n+23)


We get rid of parentheses

6n-27n-23+6=0

We add all the numbers together, and all the variables

-21n-17=0

We move all terms containing n to the left, all other terms to the right

-21n=17

n=17/-21

n=-17/21