3(2n+2)=9(3n+6)+9

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Solution for 3(2n+2)=9(3n+6)+9 equation: 



3(2n+2)=9(3n+6)+9

We move all terms to the left:

3(2n+2)-(9(3n+6)+9)=0

We multiply parentheses

6n-(9(3n+6)+9)+6=0



We calculate terms in parentheses: -(9(3n+6)+9), so:

9(3n+6)+9

We multiply parentheses

27n+54+9

We add all the numbers together, and all the variables

27n+63

Back to the equation:

-(27n+63)



We get rid of parentheses

6n-27n-63+6=0

We add all the numbers together, and all the variables

-21n-57=0

We move all terms containing n to the left, all other terms to the right

-21n=57

n=57/-21

n=-2+5/7

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