3(2n+4)+n=40

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Solution for 3(2n+4)+n=40 equation: 



3(2n+4)+n=40

We move all terms to the left:

3(2n+4)+n-(40)=0

We add all the numbers together, and all the variables

n+3(2n+4)-40=0

We multiply parentheses

n+6n+12-40=0

We add all the numbers together, and all the variables

7n-28=0

We move all terms containing n to the left, all other terms to the right

7n=28

n=28/7

n=4

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