3(2n+4)-3n=-4(3n+5)-n

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Solution for 3(2n+4)-3n=-4(3n+5)-n equation: 



3(2n+4)-3n=-4(3n+5)-n

We move all terms to the left:

3(2n+4)-3n-(-4(3n+5)-n)=0

We add all the numbers together, and all the variables

-3n+3(2n+4)-(-4(3n+5)-n)=0

We multiply parentheses

-3n+6n-(-4(3n+5)-n)+12=0



We calculate terms in parentheses: -(-4(3n+5)-n), so:

-4(3n+5)-n

We add all the numbers together, and all the variables

-1n-4(3n+5)

We multiply parentheses

-1n-12n-20

We add all the numbers together, and all the variables

-13n-20

Back to the equation:

-(-13n-20)



We add all the numbers together, and all the variables

3n-(-13n-20)+12=0

We get rid of parentheses

3n+13n+20+12=0

We add all the numbers together, and all the variables

16n+32=0

We move all terms containing n to the left, all other terms to the right

16n=-32

n=-32/16

n=-2

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