3(2n+4)=9(4n+3)+7

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Solution for 3(2n+4)=9(4n+3)+7 equation:



3(2n+4)=9(4n+3)+7
We move all terms to the left:
3(2n+4)-(9(4n+3)+7)=0
We multiply parentheses
6n-(9(4n+3)+7)+12=0
We calculate terms in parentheses: -(9(4n+3)+7), so:
9(4n+3)+7
We multiply parentheses
36n+27+7
We add all the numbers together, and all the variables
36n+34
Back to the equation:
-(36n+34)
We get rid of parentheses
6n-36n-34+12=0
We add all the numbers together, and all the variables
-30n-22=0
We move all terms containing n to the left, all other terms to the right
-30n=22
n=22/-30
n=-11/15

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