3(2n+5)-4(n-2)=30

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Solution for 3(2n+5)-4(n-2)=30 equation: 



3(2n+5)-4(n-2)=30

We move all terms to the left:

3(2n+5)-4(n-2)-(30)=0

We multiply parentheses

6n-4n+15+8-30=0

We add all the numbers together, and all the variables

2n-7=0

We move all terms containing n to the left, all other terms to the right

2n=7

n=7/2

n=3+1/2

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