3(2n+5)=6(9n+1)+4

Solution for 3(2n+5)=6(9n+1)+4 equation:

3(2n+5)=6(9n+1)+4

We move all terms to the left:

3(2n+5)-(6(9n+1)+4)=0

We multiply parentheses

6n-(6(9n+1)+4)+15=0


We calculate terms in parentheses: -(6(9n+1)+4), so:

6(9n+1)+4

We multiply parentheses

54n+6+4

We add all the numbers together, and all the variables

54n+10

Back to the equation:

-(54n+10)


We get rid of parentheses

6n-54n-10+15=0

We add all the numbers together, and all the variables

-48n+5=0

We move all terms containing n to the left, all other terms to the right

-48n=-5

n=-5/-48

n=5/48