3(2n+5)=7(3n+2)+7

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Solution for 3(2n+5)=7(3n+2)+7 equation: 



3(2n+5)=7(3n+2)+7

We move all terms to the left:

3(2n+5)-(7(3n+2)+7)=0

We multiply parentheses

6n-(7(3n+2)+7)+15=0



We calculate terms in parentheses: -(7(3n+2)+7), so:

7(3n+2)+7

We multiply parentheses

21n+14+7

We add all the numbers together, and all the variables

21n+21

Back to the equation:

-(21n+21)



We get rid of parentheses

6n-21n-21+15=0

We add all the numbers together, and all the variables

-15n-6=0

We move all terms containing n to the left, all other terms to the right

-15n=6

n=6/-15

n=-2/5

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