3(2n-2)=(2n+1)+7

Solution for 3(2n-2)=(2n+1)+7 equation:

3(2n-2)=(2n+1)+7

We move all terms to the left:

3(2n-2)-((2n+1)+7)=0

We multiply parentheses

6n-((2n+1)+7)-6=0


We calculate terms in parentheses: -((2n+1)+7), so:

(2n+1)+7

We get rid of parentheses

2n+1+7

We add all the numbers together, and all the variables

2n+8

Back to the equation:

-(2n+8)


We get rid of parentheses

6n-2n-8-6=0

We add all the numbers together, and all the variables

4n-14=0

We move all terms containing n to the left, all other terms to the right

4n=14

n=14/4

n=3+1/2