3(2n-2)=2(3n-3)

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Solution for 3(2n-2)=2(3n-3) equation: 



3(2n-2)=2(3n-3)

We move all terms to the left:

3(2n-2)-(2(3n-3))=0

We multiply parentheses

6n-(2(3n-3))-6=0



We calculate terms in parentheses: -(2(3n-3)), so:

2(3n-3)

We multiply parentheses

6n-6

Back to the equation:

-(6n-6)



We get rid of parentheses

6n-6n+6-6=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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