3(2n-3)=6(n+1)-15

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Solution for 3(2n-3)=6(n+1)-15 equation: 



3(2n-3)=6(n+1)-15

We move all terms to the left:

3(2n-3)-(6(n+1)-15)=0

We multiply parentheses

6n-(6(n+1)-15)-9=0



We calculate terms in parentheses: -(6(n+1)-15), so:

6(n+1)-15

We multiply parentheses

6n+6-15

We add all the numbers together, and all the variables

6n-9

Back to the equation:

-(6n-9)



We get rid of parentheses

6n-6n+9-9=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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