3(2n-4)-4(5-2n)=3(n-2)+5(4n+n)+2

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Solution for 3(2n-4)-4(5-2n)=3(n-2)+5(4n+n)+2 equation: 



3(2n-4)-4(5-2n)=3(n-2)+5(4n+n)+2

We move all terms to the left:

3(2n-4)-4(5-2n)-(3(n-2)+5(4n+n)+2)=0

We add all the numbers together, and all the variables

3(2n-4)-4(-2n+5)-(3(n-2)+5(+5n)+2)=0

We multiply parentheses

6n+8n-(3(n-2)+5(+5n)+2)-12-20=0



We calculate terms in parentheses: -(3(n-2)+5(+5n)+2), so:

3(n-2)+5(+5n)+2

We multiply parentheses

3n+25n-6+2

We add all the numbers together, and all the variables

28n-4

Back to the equation:

-(28n-4)



We add all the numbers together, and all the variables

14n-(28n-4)-32=0

We get rid of parentheses

14n-28n+4-32=0

We add all the numbers together, and all the variables

-14n-28=0

We move all terms containing n to the left, all other terms to the right

-14n=28

n=28/-14

n=-2

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