3(2n-4)=6(n-2)

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Solution for 3(2n-4)=6(n-2) equation:



3(2n-4)=6(n-2)
We move all terms to the left:
3(2n-4)-(6(n-2))=0
We multiply parentheses
6n-(6(n-2))-12=0
We calculate terms in parentheses: -(6(n-2)), so:
6(n-2)
We multiply parentheses
6n-12
Back to the equation:
-(6n-12)
We get rid of parentheses
6n-6n+12-12=0
We add all the numbers together, and all the variables
=0
n=0/1
n=0

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