3(2n-5)=6+2(n-3)

Solution for 3(2n-5)=6+2(n-3) equation:

3(2n-5)=6+2(n-3)

We move all terms to the left:

3(2n-5)-(6+2(n-3))=0

We multiply parentheses

6n-(6+2(n-3))-15=0


We calculate terms in parentheses: -(6+2(n-3)), so:

6+2(n-3)

determiningTheFunctionDomain
2(n-3)+6

We multiply parentheses

2n-6+6

We add all the numbers together, and all the variables

2n

Back to the equation:

-(2n)


We add all the numbers together, and all the variables

4n-15=0

We move all terms containing n to the left, all other terms to the right

4n=15

n=15/4

n=3+3/4