3(2p+4)+(3p-4)=43

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Solution for 3(2p+4)+(3p-4)=43 equation: 



3(2p+4)+(3p-4)=43

We move all terms to the left:

3(2p+4)+(3p-4)-(43)=0

We multiply parentheses

6p+(3p-4)+12-43=0

We get rid of parentheses

6p+3p-4+12-43=0

We add all the numbers together, and all the variables

9p-35=0

We move all terms containing p to the left, all other terms to the right

9p=35

p=35/9

p=3+8/9

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