3(2p+6)+4(p+3)+6(5p-1)=10(p-3)+6(p-1

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Solution for 3(2p+6)+4(p+3)+6(5p-1)=10(p-3)+6(p-1 equation: 



3(2p+6)+4(p+3)+6(5p-1)=10(p-3)+6(p-1

We move all terms to the left:

3(2p+6)+4(p+3)+6(5p-1)-(10(p-3)+6(p-1)=0

We multiply parentheses

6p+4p+30p-(10(p-3)+6(p-1)+18+12-6=0

We add all the numbers together, and all the variables

40p-(10(p-3)+6(p-1)+18+12-6=0

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