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3(2p-5)=5(p-4)+p+5
We move all terms to the left:
3(2p-5)-(5(p-4)+p+5)=0
We multiply parentheses
6p-(5(p-4)+p+5)-15=0
We calculate terms in parentheses: -(5(p-4)+p+5), so:We get rid of parentheses
5(p-4)+p+5
We add all the numbers together, and all the variables
p+5(p-4)+5
We multiply parentheses
p+5p-20+5
We add all the numbers together, and all the variables
6p-15
Back to the equation:
-(6p-15)
6p-6p+15-15=0
We add all the numbers together, and all the variables
=0
p=0/1
p=0
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