3(2q+1)=5(q-2)+7

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Solution for 3(2q+1)=5(q-2)+7 equation: 



3(2q+1)=5(q-2)+7

We move all terms to the left:

3(2q+1)-(5(q-2)+7)=0

We multiply parentheses

6q-(5(q-2)+7)+3=0



We calculate terms in parentheses: -(5(q-2)+7), so:

5(q-2)+7

We multiply parentheses

5q-10+7

We add all the numbers together, and all the variables

5q-3

Back to the equation:

-(5q-3)



We get rid of parentheses

6q-5q+3+3=0

We add all the numbers together, and all the variables

q+6=0

We move all terms containing q to the left, all other terms to the right

q=-6

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