3(2q+5)=(7+4q)

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Solution for 3(2q+5)=(7+4q) equation: 



3(2q+5)=(7+4q)

We move all terms to the left:

3(2q+5)-((7+4q))=0

We add all the numbers together, and all the variables

3(2q+5)-((4q+7))=0

We multiply parentheses

6q-((4q+7))+15=0



We calculate terms in parentheses: -((4q+7)), so:

(4q+7)

We get rid of parentheses

4q+7

Back to the equation:

-(4q+7)



We get rid of parentheses

6q-4q-7+15=0

We add all the numbers together, and all the variables

2q+8=0

We move all terms containing q to the left, all other terms to the right

2q=-8

q=-8/2

q=-4

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