3(2q+5)=4q+21

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Solution for 3(2q+5)=4q+21 equation: 



3(2q+5)=4q+21

We move all terms to the left:

3(2q+5)-(4q+21)=0

We multiply parentheses

6q-(4q+21)+15=0

We get rid of parentheses

6q-4q-21+15=0

We add all the numbers together, and all the variables

2q-6=0

We move all terms containing q to the left, all other terms to the right

2q=6

q=6/2

q=3

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