3(2q+r)+5(4q-7r)=

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Solution for 3(2q+r)+5(4q-7r)= equation:


Simplifying
3(2q + r) + 5(4q + -7r) = 0
(2q * 3 + r * 3) + 5(4q + -7r) = 0
(6q + 3r) + 5(4q + -7r) = 0
6q + 3r + (4q * 5 + -7r * 5) = 0
6q + 3r + (20q + -35r) = 0

Reorder the terms:
6q + 20q + 3r + -35r = 0

Combine like terms: 6q + 20q = 26q
26q + 3r + -35r = 0

Combine like terms: 3r + -35r = -32r
26q + -32r = 0

Solving
26q + -32r = 0

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '32r' to each side of the equation.
26q + -32r + 32r = 0 + 32r

Combine like terms: -32r + 32r = 0
26q + 0 = 0 + 32r
26q = 0 + 32r
Remove the zero:
26q = 32r

Divide each side by '26'.
q = 1.230769231r

Simplifying
q = 1.230769231r

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