3(2q-2)-6=3(q+2)

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Solution for 3(2q-2)-6=3(q+2) equation: 



3(2q-2)-6=3(q+2)

We move all terms to the left:

3(2q-2)-6-(3(q+2))=0

We multiply parentheses

6q-(3(q+2))-6-6=0



We calculate terms in parentheses: -(3(q+2)), so:

3(q+2)

We multiply parentheses

3q+6

Back to the equation:

-(3q+6)



We add all the numbers together, and all the variables

6q-(3q+6)-12=0

We get rid of parentheses

6q-3q-6-12=0

We add all the numbers together, and all the variables

3q-18=0

We move all terms containing q to the left, all other terms to the right

3q=18

q=18/3

q=6

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