3(2r+1)+7(6r-1)=5(12r-7)+19

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Solution for 3(2r+1)+7(6r-1)=5(12r-7)+19 equation: 



3(2r+1)+7(6r-1)=5(12r-7)+19

We move all terms to the left:

3(2r+1)+7(6r-1)-(5(12r-7)+19)=0

We multiply parentheses

6r+42r-(5(12r-7)+19)+3-7=0



We calculate terms in parentheses: -(5(12r-7)+19), so:

5(12r-7)+19

We multiply parentheses

60r-35+19

We add all the numbers together, and all the variables

60r-16

Back to the equation:

-(60r-16)



We add all the numbers together, and all the variables

48r-(60r-16)-4=0

We get rid of parentheses

48r-60r+16-4=0

We add all the numbers together, and all the variables

-12r+12=0

We move all terms containing r to the left, all other terms to the right

-12r=-12

r=-12/-12

r=1

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