3(2r+2)+r+5=-10

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Solution for 3(2r+2)+r+5=-10 equation: 



3(2r+2)+r+5=-10

We move all terms to the left:

3(2r+2)+r+5-(-10)=0

We add all the numbers together, and all the variables

r+3(2r+2)+15=0

We multiply parentheses

r+6r+6+15=0

We add all the numbers together, and all the variables

7r+21=0

We move all terms containing r to the left, all other terms to the right

7r=-21

r=-21/7

r=-3

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