3(2r+3)-4(r+2)=21

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Solution for 3(2r+3)-4(r+2)=21 equation: 


Simplifying
3(2r + 3) + -4(r + 2) = 21

Reorder the terms:
3(3 + 2r) + -4(r + 2) = 21
(3 * 3 + 2r * 3) + -4(r + 2) = 21
(9 + 6r) + -4(r + 2) = 21

Reorder the terms:
9 + 6r + -4(2 + r) = 21
9 + 6r + (2 * -4 + r * -4) = 21
9 + 6r + (-8 + -4r) = 21

Reorder the terms:
9 + -8 + 6r + -4r = 21

Combine like terms: 9 + -8 = 1
1 + 6r + -4r = 21

Combine like terms: 6r + -4r = 2r
1 + 2r = 21

Solving
1 + 2r = 21

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2r = 21 + -1

Combine like terms: 1 + -1 = 0
0 + 2r = 21 + -1
2r = 21 + -1

Combine like terms: 21 + -1 = 20
2r = 20

Divide each side by '2'.
r = 10

Simplifying
r = 10

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