3(2r+7)+2(4m+5)=33

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Solution for 3(2r+7)+2(4m+5)=33 equation: 


Simplifying
3(2r + 7) + 2(4m + 5) = 33

Reorder the terms:
3(7 + 2r) + 2(4m + 5) = 33
(7 * 3 + 2r * 3) + 2(4m + 5) = 33
(21 + 6r) + 2(4m + 5) = 33

Reorder the terms:
21 + 6r + 2(5 + 4m) = 33
21 + 6r + (5 * 2 + 4m * 2) = 33
21 + 6r + (10 + 8m) = 33

Reorder the terms:
21 + 10 + 8m + 6r = 33

Combine like terms: 21 + 10 = 31
31 + 8m + 6r = 33

Solving
31 + 8m + 6r = 33

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-31' to each side of the equation.
31 + 8m + -31 + 6r = 33 + -31

Reorder the terms:
31 + -31 + 8m + 6r = 33 + -31

Combine like terms: 31 + -31 = 0
0 + 8m + 6r = 33 + -31
8m + 6r = 33 + -31

Combine like terms: 33 + -31 = 2
8m + 6r = 2

Add '-6r' to each side of the equation.
8m + 6r + -6r = 2 + -6r

Combine like terms: 6r + -6r = 0
8m + 0 = 2 + -6r
8m = 2 + -6r

Divide each side by '8'.
m = 0.25 + -0.75r

Simplifying
m = 0.25 + -0.75r

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